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5p^2-29p-6=0
a = 5; b = -29; c = -6;
Δ = b2-4ac
Δ = -292-4·5·(-6)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-31}{2*5}=\frac{-2}{10} =-1/5 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+31}{2*5}=\frac{60}{10} =6 $
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